Timeline for Is there such a thing as a "drive tire"?
Current License: CC BY-SA 3.0
11 events
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Jan 21, 2017 at 9:27 | comment | added | Criggie | The Model T ford had a drive wheel - it was literally a single rear wheel connected to the drive shaft. That's the only "single drive wheel" I can recall. | |
Dec 28, 2015 at 17:29 | comment | added | cloudnyn3 | Thank you both DucatiKiller and HandyHowie for the corrections you made! | |
Dec 28, 2015 at 16:43 | comment | added | DucatiKiller | If I could upvote this answer twice, I would...but I can't. Great answer. | |
Dec 23, 2015 at 15:58 | history | edited | DucatiKiller | CC BY-SA 3.0 |
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Nov 23, 2015 at 17:12 | comment | added | HandyHowie | There are various forms of LSD. Probably the simplest one to picture has friction plates like on a clutch between the outputs of the differential. If one wheel looses traction, the friction plates stop it spinning freely, in so doing keeps torque applied to the other wheel. | |
Nov 23, 2015 at 16:08 | comment | added | cloudnyn3 | So, whats the difference between a conventional open differential and modern differential? I understand what an LSD is but it seems just like an open differential. I'm also explaining myself wrong, what I'm saying is that if one wheel looses traction for some reason, it limits the torque applied to the wheel with least traction; Thus limiting the torque of both of them. | |
Nov 23, 2015 at 16:03 | comment | added | HandyHowie | That is the point, an open differential always has equal torque to both wheels. One may turn faster than the other, but they will both have equal torque. | |
Nov 23, 2015 at 15:52 | comment | added | cloudnyn3 | The way he worded it made it sound like he thought that at ALL times each wheel has equal torque applied to it no matter what. I was just trying to make it clear that, thats not the case. The entire purpose of a conventional open differential is to supply torque to the wheel with the best traction. | |
Nov 23, 2015 at 10:01 | comment | added | HandyHowie | cloudnyn3 - I hope you don't mind me saying this, but @DanW was correct about equal torque to each wheel in an open differential. That is why if one wheel slips on ice (it has zero torque), then the opposite wheel stops moving (zero torque). | |
Nov 23, 2015 at 5:57 | history | edited | cloudnyn3 | CC BY-SA 3.0 |
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Nov 23, 2015 at 4:16 | history | answered | cloudnyn3 | CC BY-SA 3.0 |