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Need help sussing out something. The background: I have a 3.0 Ford Vulcan V6 in a 2000 Taurus (a 60º V6). Was changing spark plugs, the hex for piston #2 broke off above the threads. Gonna try using a square-cut extractor to remove the remains stuck in the head, but I need to set the piston at BDC first.

How can I use the position of pistons 4-6 (because they are more easily accessible) to determine when piston #2 is BDC?

Found this diagram online:

enter image description here

The firing order is supposedly 1-4-2-5-3-6. So if I start with #1 at TDC, the cylinder fires, rotates the crank 60º, moving #4 to TDC and firing it, then rotating 60º, rotating #2 to TDC and firing it, and so on? I believe the TDC-BDC pairings should be like this, correct?

1-5

4-3

2-6

5-1

3-4

6-2

So if I want to set #2 to BDC, I should rotate the crank so that #6 is at TDC. Right?

Thanks!

  • I think the pairs will be 1&4, 2&5, 3&6 as they will be on the same crank throws... – Solar Mike Jun 4 at 5:29

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