Need help sussing out something. The background: I have a 3.0 Ford Vulcan V6 in a 2000 Taurus (a 60º V6). Was changing spark plugs, the hex for piston #2 broke off above the threads. Gonna try using a square-cut extractor to remove the remains stuck in the head, but I need to set the piston at BDC first.
How can I use the position of pistons 4-6 (because they are more easily accessible) to determine when piston #2 is BDC?
Found this diagram online:
The firing order is supposedly 1-4-2-5-3-6. So if I start with #1 at TDC, the cylinder fires, rotates the crank 60º, moving #4 to TDC and firing it, then rotating 60º, rotating #2 to TDC and firing it, and so on? I believe the TDC-BDC pairings should be like this, correct?
So if I want to set #2 to BDC, I should rotate the crank so that #6 is at TDC. Right?