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There are 2 cars, car A and car B.
Car B is 20% heavier than car A.
We all know that this means that these 2 cars will have same power if car B at the same RPM (revolution) has 20% more Nm.

Can the torque be mathematically equated?

For example, if car A has torque of 100/1500 and car B has torque of 150/1750. Can we deduct the 2nd value (150/1750) to x / 1500? Is this the mathematically correct way to determine the torque decrease?

If I did not write this clearly, please ask me to clarify. This data is very important to me and I was unable to find this info on the Net.

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What is the reason you are trying to do this calculation?Are you comparing vehicles? – mikes Oct 2 '12 at 0:51
I don't get what you're asking? Neither power nor torque bear any relationship to the vehicle weight, hence why we have a "power to weight ratio" so we can more realistically compare two vehicles. – Nick C Oct 2 '12 at 12:32
@mikes yes, trying to compare cars – salone Oct 2 '12 at 13:52
@nick heavier car means more resistance means that heavier car having the same torque as lighter car will be slower, right?! ;) – salone Oct 2 '12 at 13:53
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Not necessarily, it would depend on things like the gear ratios, the size of the wheels, the torque curve of the engine and quite a few other factors... Torque as a number is purely a measure of how much turning force the engine can produce. It also depends on what you mean by faster - top speed or acceleration? – Nick C Oct 2 '12 at 15:20
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